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1.50 × 104 J of energy is transferred thermally into a huge tank filled with liquid water. The water temperature remains constant at 10.0 ∘C during the process.Part ABy how much does the entropy of the water change?

Respuesta :

drpelezo

Answer:

53j/k

Explanation:

ΔH = TΔS => ΔS = ΔH/T = 1.5 x 10⁴ joules/283 Kelvin = 53 joules/K

pstnonsonjoku

The entropy of the system is 53 J/K.

Entropy is defined as the degree of disorder of a system. The entropy of a system is obtained using the formula;

ΔS = ΔH/T

Where;

ΔS = entropy change

ΔH = enthalpy change

T = temperature

Now substituting values;

ΔS = 1.50 × 10^4 J/(10∘C + 273)

ΔS = 1.50 × 10^4 J/283

ΔS = 53 J/K

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