AD and MN are chords that intersect at point B what is the length of line segment MN?
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Answer:
[tex]MN=18\ units[/tex]
Step-by-step explanation:
we know that
The Intersecting Chord Theorem, states that When two chords intersect each other inside a circle, the products of their segments are equal.
so
In this problem
[tex]AB*BD=MB*BN[/tex]
substitute
[tex](9)(x+1)=(x-1)(15)\\ \\9x+9=15x-15\\ \\15x-9x=9+15\\ \\ 6x=24\\ \\x=4\ units[/tex]
Find the length of line segment MN
[tex]MN=MB+BN=(x-1)+15=x+14[/tex]
substitute the value of x
[tex]MN=4+14=18\ units[/tex]
Answer:
MN = 18
Step-by-step explanation:
AD and MN are two chords intersecting inside the circle at point B.
As we know from intersecting chords theorem.
AB × BD = BN × BM
So 9(x-1) = 15 (x-1)
9x + 9 = 15x - 15
15x - 9x = 15 + 9
6x = 24
x = 4
and MN = (x-1) + 15
= (x + 14)
= 4 + 14 ( By putting x = 4 )
= (18)
Therefore, MN = 18 is the answer.