apowers3102 apowers3102
  • 10-07-2019
  • Mathematics
contestada

Evaluate the sum or explain why it diverges: Sigma^infinity_k = 3(-3/2)^k

Respuesta :

botellok
botellok botellok
  • 20-07-2019

Answer:

Step-by-step explanation:

Remember that in the geometric serie if | r | < 1 the serie converges and if | r | ≥1 the serie diverges.

I suppose that the serie starts at 0, so using the geometric serie with r = | [tex]\frac{-3}{2}[/tex] | > 1 the serie diverges.

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