Answer:
BD = 10
Step-by-step explanation:
Since AC is a tangent to the circle at B then ∠ABD = 90°
Using Pythagoras' identity in the right triangle ABD with hypotenuse AD
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
BD² + AB² = AD²
BD² + 24² = 26²
BD² + 576 = 676 ( subtract 576 from both sides )
BD² = 100 ( take the square root of both sides )
BD = [tex]\sqrt{100}[/tex] = 10
