NEED HELP WITH MATH QUESTION ITS ABOUT FINDING AREA OF A TRIANGLE !! I WOULD BE REALLY GRATEFUL IS SOMEONE HELPED ME WITH A FEW QUESTIONS AFTER THIS

Answer:
65.8 in²
Step-by-step explanation:
Given a triangle with 2 sides and the included angle then the area (A) is
A = 0.5 × a × b × sinΘ
where a, b are the 2 sides and Θ the included angle
here a = 18, b = 12 and Θ = 147°, hence
A = 0. 5 × 18 × 12 × sin147°
= 108 × sin147° ≈ 65.8 ( to the nearest tenth )
Answer:
The area of triangle is 59.2 in².
Step-by-step explanation:
If a, b and c are three sides of a triangle then the area of triangle by heron's formula is
[tex]A=\sqrt{s(s-a)(s-b)(s-c)[/tex] .... (1)
where,
[tex]s=\frac{a+b+c}{2}[/tex]
From the given figure it is clear that the length of sides are 12 in, 18 in and 28.8 in. The value of s is
[tex]s=\frac{12+18+28.8}{2}=29.4[/tex]
Substitute s=29.4, a=12, b=18 and c=28.8 in equation (1).
[tex]A=\sqrt{29.4(29.4-12)(29.4-18)(29.4-28.8)}[/tex]
[tex]A=\sqrt{3499.0704}[/tex]
[tex]A=59.15294[/tex]
[tex]A\approx 59.2[/tex]
Therefore the area of triangle is 59.2 in².