Answer:
the amount invested at 1% = $4100
the amount invested at 9% = $2600
Step-by-step explanation:
Hello
let
A=amount invested at 1%
B=amount invested at 9%
the total amount invested is % 6700, so
A+B=6700 (1)
the profits generated by A= (c)
[tex]c=A\frac{1}{100}[/tex]
the profits generated by B=(d)
[tex]d=B\frac{9}{100}[/tex]
the total profit is $275,so
[tex]275=\frac{A}{100}+0.09B\\ A=100*(275-0.09B)\\A=27500-9B\\\\replacing \ in \ (1)\\27500-9B+B=6700\\27500-6700=8B\\B=\frac{20800}{8}\\ B=2600[/tex]
[tex]A=6700-B\\A=6700-2600\\A=4100[/tex]
the amount invested at 1% = $4100
the amount invested at 9% = $2600
I hope it helps
