Write a cost function for the problem. Assume that the relationship is linear. Fixed cost, $410; 5 items cost $5,590 to produce. A. C(x)-1.036x + 410 ? B. C(x)= 1,036x +5,590 ? ?. ?(x) 2,072x +5,590 O D. C(x)-2,072x+410

Respuesta :

Answer:

The required cost function is [tex]C(x)=1036x+410[/tex].

Step-by-step explanation:

It is given that the cost function represents a linear relationship.

The fixed cost is $410 and the cost of 5 items is $5,590. It means the linear function passes through the points (0,410) and (5,5590).

If a line passes through two points then the equation of line is

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The equation of cost function is

[tex]y-410=\frac{5590-410}{5-0}(x-0)[/tex]

[tex]y-410=\frac{5180}{5}(x)[/tex]

[tex]y-410=36x[/tex]

[tex]y-410=1036x[/tex]

Add 410 on both the sides.

[tex]y=1036x+410[/tex]

The required cost function is

[tex]C(x)=1036x+410[/tex]

Therefore the required cost function is [tex]C(x)=1036x+410[/tex].

The required cost function is [tex]\rm C(x)= 1,036x +410[/tex].

Given

The relationship is linear.

Fixed cost, $410; 5 items cost $5,590 to produce.

What is a linear equation?

An equation between two variables that gives a straight line when plotted on a graph.

The standard form represents the linear equation;

[tex]\rm y=mx+c[/tex]

The fixed cost is $410 and the cost of the 5 items is $5,590. It means the linear function passes through the points (0,410) and (5,5590).

If a line passes through two points then the equation of a line is;

[tex]\rm y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-410=\dfrac{5590-410}5-0}(x-0)\\\\y-410=\dfrac{5180}{5}x\\\\y-410=1036x\\\\y=1036x+410\\\\C(x)=1036x+410[/tex]

Hence, the required cost function is [tex]\rm C(x)= 1,036x +410[/tex].

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