Answer:
3 volts
Explanation:
Number of turns in primary coil = [tex]N_{p}[/tex] = 100
Number of turns in secondary coil = [tex]N_{s}[/tex] = 200
Voltage across primary coil = [tex]V_{p}[/tex] = 1.5 volts
Voltage across secondary coil = [tex]V_{s}[/tex] = ?
In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.
[tex]\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }\\[/tex]
Using the given values, we get:
[tex]\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3[/tex]
Thus, the voltage measure across secondary coil would be 3 volts
