Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
We have the slope m = -5, and the point (-1, -3). Substitute:
[tex]y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)[/tex]
Convert to the slope-intercept form (y = mx + b):
[tex]y+3=-5(x+1)[/tex] use the distributive property
[tex]y+3=-5x-5[/tex] subtract 3 from both sides
[tex]y=-5x-8[/tex]