Answer:
The quantity of heat required to increase the temperature of the object from 6°C to 12°C is 3Q
Explanation:
Heat capacity is the quantity of heat required to increase the temperature of an object.
Q = mcΔθ
where;
Q is the quantity of heat
m is the mass of the object
c is specific heat capacity of the object
Δθ is change in temperature = T₂ - T₁
For the first sentence of this question;
Q = mc(6-4)
Q = mc(2)
Q = 2mc
For the second sentence of this question;
Let Q₂ be the quantity of heat required to increase the temperature of the object from 6°C to 12°C
Q₂ = mcΔθ
Q₂ = mc(12-6)
Q₂ = mc(6)
Q₂ = 6mc
Q₂ = 3(2mc)
Recall, Q = 2mc
Thus, Q₂ = 3Q
