Answer:
[tex]w_{damped}= 4.76[/tex] s^-1
Explanation:
The mathematical relationship is
[tex]w_{damped}=w_{undamped} *\sqrt{1-(\frac{c}{2\sqrt{km}})^{2}}[/tex]
where:
c is the damper constant
k is the spring constant
m is the mass
ω_undamped is the natural frequency
ω_damped is the damped frequency
[tex]w_{undamped} =\sqrt{\frac{k}{m}}=4.79[/tex] s^-1
[tex]w_{damped}= 4.79 *\sqrt{1-(\frac{2}{2\sqrt{295*13}})^{2}}[/tex]
[tex]w_{damped}= 4.76[/tex] s^-1
