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A heat engine operates between a hot reservoir at 2000°C and the atmosphere (cold reservoir) at 25°C. it produces 50 MW of power while rejecting 40 MW of waste heat. Determine the maximum possible thermal efficiency of the engine in percent.

Respuesta :

Answer:

55.56%

Explanation:

Given data

Temprature of hot reservior =2000°c=2273k

Temprature of Cold reservior=25°c=298k

Power produced by engine=50MW

Heat rejected =40MW

we know that Effeciency(η) of heat engine=[tex]\frac{Work produced}{heat supplied}[/tex]

Also we know that

heat supplied[tex]\left ({Q_s} \right )=work produced{W}+Heat rejected{Q_r}[/tex]

Q_s=50+40=90MW

η=[tex]\frac{W}{Q_s}[/tex]

η=[tex]\frac{50}{90}[/tex]

η=55.55%