Answer:227.56 mm
Explanation:
Given data
Elastic modulus[tex]\left ( E\right )[/tex]= 117 GPa
Diameter[tex]\left ( d\right )[/tex]=3.6mm
force applied[tex]\left ( F\right )[/tex]=2460N
Area of cross-section[tex]\left ( A\right )[/tex]=[tex]\frac{\pi}{4}\times d^{2}[/tex]=10.18[tex]mm^{2}[/tex]
and change in length is given by
[tex]\Delta L[/tex]=[tex]\frac{FL}{AE}[/tex]
[tex]\Delta {0.47\times 10^{-3}}[/tex]=[tex]\frac{2460\times L}{10.180\times 117\times 10^{3}}[/tex]
L=[tex]0.47\times 10^{-3}\times 10.18\times 117\times 10^{3][/tex]
L=227.56 mm
