Answer:
[tex]\boxed{\text{7.68 s}}[/tex]
Step-by-step explanation:
s(t) = 16t²
[tex]\begin{array}{rcl}944 & = & 16t^{2}\\t^{2} & = & 59\\t & = & \sqrt{59}\\ & = &\mathbf{7.68}\\\end{array}\\\text{It would take the object } \boxed{\textbf{7.68 s}} \text{ to reach the ground}[/tex]