Respuesta :
The average current passing through a device is given by:
I = Q/Δt
I is the average current
Q is the amount of charge that has passed through the device
Δt is the amount of elapsed time
Given values:
Q = 600C
Δt = 0.500hr = 1800s
Plug in the values and solve for I:
I = 600/1800
I = 0.333A
The average current flowing in the flashlight bulb is 0.333 A
The given parameters:
quantity of the charge, Q = 600 C
time of the current flow, t = 0.5 hour
To find:
- the average current, I
The average current is calculated from quantity of charge that flows in the given time period:
Q = It
where:
I is the average current
Q is the quantity of the charge
t is the time period
From the equation above, make the average current the subject of the formula:
[tex]I = \frac{Q}{t} \\\\I = \frac{600 \ C}{0.5 \ hr \times 3600 \ s} \\\\I = \frac{600 \ C}{1800 \ s} \\\\I = 0.333 \ A[/tex]
Thus, the average current is 0.333 A
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