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A total of 600 C of charge passes through flashlight bulb in 0.500 hr. What is the average current? Give your answer in A.

Respuesta :

The average current passing through a device is given by:

I = Q/Δt

I is the average current

Q is the amount of charge that has passed through the device

Δt is the amount of elapsed time

Given values:

Q = 600C

Δt = 0.500hr = 1800s

Plug in the values and solve for I:

I = 600/1800

I = 0.333A

The average current  flowing in the flashlight bulb is 0.333 A

The given parameters:

quantity of the charge, Q = 600 C

time of the current flow, t = 0.5 hour

To find:

  • the average current, I

The average current is calculated from quantity of charge that flows in the given time period:

Q = It

where:

I is the average current

Q is the quantity of the charge

t is the time period

From the equation above, make the average current the subject of the formula:

[tex]I = \frac{Q}{t} \\\\I = \frac{600 \ C}{0.5 \ hr \times 3600 \ s} \\\\I = \frac{600 \ C}{1800 \ s} \\\\I = 0.333 \ A[/tex]

Thus, the average current is 0.333 A

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