Respuesta :
Answer:
The graph in the attached figure
Step-by-step explanation:
Let
x -----> the number of stools
y ----> the number of recliners
we know that
[tex]x+y \leq 50[/tex] -----> inequality A
[tex]x\geq 20[/tex] ----> inequality B
using a graphing tool
The solution is the triangular shaded area (remember that the number of seats cannot be a negative number)
see the attached figure
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Answer:
The below graph represents the solution.
Step-by-step explanation:
Here, x represents the number of stools and y represents the number of recliners,
∵ total seats ≤ 50
⇒ x + y ≤ 50,
Also, owner wants at least 20 of the seats to be stools,
i.e. x ≥ 20,
And, the remaining seats to be recliners.
Related equation of the inequality x + y ≤ 50,
x + y = 50
if x = 0, y = 50
if y = 0, x = 50,
So, join the points (0, 50) and (50, 0) in the coordinate plan,
0 + 0 ≤ 50, ( true )
Thus, the shaded region will contain the origin.
For graphing x ≥ 20,
Shade the region left side of the line x = 20.
By above explanation,
We obtain the feasible region that shows the solution to the system of inequalities. ( shown below )
Note : numbers of thing can not be negative,
i.e. x ≥ 0 and y ≥ 0
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