In one type of dog, black spots (B) are dominant over brown spots (b) and long tails (L) are dominant over short tails (l). Use the dihybrid cross for parents with the genotypes BBLl and BbLl and determine the likelihood of offspring with the phenotype of brown spots and short tails.

BL Bl BL Bl
BL BBLL BBLl BBLL BBLl
Bl BBLl BBll BBLl BBll
bL BbLL BbLl BbLL BbLl
bl BbLl Bbll BbLl Bbll
0%
10%
20%
50%

Question

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Respuesta :

shilohz9935 shilohz9935 · Answer 1 · 2019-07-11T06:40:04+02:00

Answer:

There is a 0% chance of getting the phenotype of brown spots and short tails.

Explanation:

Here is a Punnett square

BL Bl BL Bl

BL BBLL BBLl BBLL BBLL

Bl BBLl BBll BBLl BBll

bL BbLL BbLl BbLL BbLl

bl BbLl Bbll BbLl Bbll

podgorica podgorica · Answer 2 · 2019-07-20T15:51:47+02:00

Answer:

Option A, 0%

Explanation:

It is given that

a) black spots (B) are dominant over brown spots (b)

b) long tails (L) are dominant over short tails (l)

Thus, the offspring with genotype "bb" will be of brown color as b is a recessive trait.

Also, offspring with genotype "ll" will have short tail as short tail is a recessive trait.

Thus, in the given punnet square genotype representing brown color and short tail together are - zero

Thus, option A is correct.