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Calculate the mass of the air contained in a room that measures 2.50 m x 5.50 m x 3.00 m if the density of air is 1.29 g/dm3.53.2 g3.13 x 10-3 g3.20 x 104 g5.32 x 104 g5.32 x 107 g

Respuesta :

skyluke89

Answer:

[tex]5.32\cdot 10^4 g[/tex]

Explanation:

First of all, we need to find the volume of the room, which is given by

[tex]V=2.50 m \cdot 5.50 m \cdot 3.00 m =41.3 m^3[/tex]

Now we  can find the mass of the air by using

[tex]m=dV[/tex]

where

[tex]d=1.29 g/dm^3[/tex] is the density of the air

[tex]V=41.3 m^3 = 41,300 dm^3[/tex] is the volume of the room

Substituting,

[tex]m=(1.29)(41300)=5.32\cdot 10^4 g[/tex]

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