A company is replacing cables with fiber optic lines in rectangular casing BCDE. If line segment DE = 3 cm and line segment BE = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line? Round your answer to the nearest hundredth.



3.54 cm

3.91 cm

4.24 cm

4.95 cm

A company is replacing cables with fiber optic lines in rectangular casing BCDE If line segment DE 3 cm and line segment BE 3 cm what is the smallest diameter o class=

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Answer:

The correct option is C.

Step-by-step explanation:

Given information: BCDE is a rectangular casing, DE = 3 cm and BE = 3 cm.

We need to find the smallest diameter of pipe that will fit the fiber optic line. It means we have to find the measure of DB.

The measure of all interior angles of a rectangle or square is 90°.

[tex]\angle DEB=90^{\circ}[/tex]

It means the DEB is right angled triangle.

According to the Pythagoras theorem:

[tex]hypotenuse^2=leg_1^2+leg_2^2[/tex]

In triangle DEB,

[tex](DB)^2=(DE)^2+(BE)^2[/tex]

[tex](DB)^2=(3)^2+(3)^2[/tex]

[tex](DB)^2=9+9[/tex]

[tex](DB)^2=18[/tex]

Taking square root both sides.

[tex]DB=\sqrt{18}[/tex]

[tex]DB=4.24264068712[/tex]

[tex]DB\approx 4.24[/tex]

Therefore the correct option is C.

Based on the information given, the smallest diameter will be C. 4.24 cm.

  • Based on the information given, it can be noted that triangle DEB us a right angle triangle. Therefore, the Pythagoras theorem can be used.

DB² = 3² + 3²

DB² = 9 + 9

DB² = 18

DB = ✓18

DB = 4.24

Therefore, the correct option is 4.24.

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