Answer : The pH of the solution is, 7.4
Explanation : Given,
pOH = 7.1
[tex]K_w=2.93\times 10^{-15}[/tex]
First we have to calculate the value of [tex]pK_w[/tex].
The expression used for the calculation of [tex]pK_w[/tex] is,
[tex]pK_w=-\log [K_w][/tex]
Now put the value of [tex]K_w[/tex] in this expression, we get:
[tex]pK_w=-\log (2.93\times 1-^{-15})[/tex]
[tex]pK_w=15-\log (2.93)[/tex]
[tex]pK_w=14.5[/tex]
Now we have to calculate the pH of the solution.
As we know that,
[tex]pH+pOH=pK_w[/tex]
Now put all the given values in this formula, we get:
[tex]pH+7.1=14.5[/tex]
[tex]pH=7.4[/tex]
Therefore, the pH of the solution is, 7.4
A solution has a pOH of 7.1 and a pH of 7.4 at 10 °C, being Kw = 2.93 × 10⁻¹⁵ at that temperature.
pH is a figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values are more alkaline.
A solution has a pOH of 7.1 at 10 °C. We can calculate the pH at this temperature using the following expression.
pH + pOH = pKw
pH = pKw - pOH
pH = -log (2.93 × 10⁻¹⁵) - 7.1 = 7.4
where,
A solution has a pOH of 7.1 and a pH of 7.4 at 10 °C, being Kw = 2.93 × 10⁻¹⁵ at that temperature.
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