A basket contains six apples and four peaches. You randomly select one piece of fruit and eat it. Then you randomly select another piece of fruit. The first piece of fruit is an apple and the second piece is a peach. Find the probability of this occuring.

Respuesta :

Answer as a fraction: 4/15

Answer as a decimal: 0.267

The decimal version is approximate rounded to three decimal places.

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Explanation:

6 apples, 4 peaches

6+4 = 10 pieces of fruit total

The probability of picking an apple is 6/10 = 3/5

After you pick and eat the apple, there are 10-1 = 9 pieces of fruit left. Also, the probability of picking a peach is 4/9, as there are 4 peaches out of 9 fruit left over.

Multiply out 3/5 and 4/9 to get (3/5)*(4/9) = (3*4)/(5*9) = 12/45 = 4/15

Using a calculator, 4/15 = 0.267 approximately.

Answer:

Fraction: [tex]\frac{4}{15}[/tex]

Decimal: [tex]0.2667[/tex]

Percent: 26.67%

Step-by-step explanation:

If the basket contains six apples and four peaches then the Total amount of fruit in the basket is (6+4) 10 pieces of fruit.

You reach in and randomly pick out an apple. Since there are only 4 apples, the probability of this happening was [tex]\frac{4}{10}[/tex] , and now there are only 9 pieces of fruit in the basket.

Now you reach in and randomly pick out a peach. Since there are 6 peaches, the probability of this happening is [tex]\frac{6}{9}[/tex]. Now we can find the probability of both of these things happening one after another by multiplying both probabilities together

[tex]\frac{4}{10} * \frac{6}{9}  = \frac{24}{90}[/tex]

[tex]\frac{24}{90} = \frac{4}{15}[/tex] ...... simplified

So we can see that the probability of you picking out an apple and a peach in sequence is [tex]\frac{4}{15}[/tex] or [tex]0.2667[/tex]

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