Respuesta :
Answer:
13 lb
Step-by-step explanation:
The horizontal component of the force is the magnitude of the force multiplied by the cosine of the angle with the horizontal.
(16 lb)·cos(35°) ≈ 13.1 lb ≈ 13 lb
Answer:
b.13 lb
Step-by-step explanation:
We are given that a boy pulls his sled with a rope .
The rope makes an angle with horizontal =[tex]35^{\circ}[/tex]
If a pull on the rope is needed to move the sled=16 pounds
We have to find the horizontal component of force
We know that horizontal component force=[tex]fcos\alpha[/tex]
Therefore, we have f=16 pound
Then, horizontal component of force=[tex]16cos 35^{\circ}[/tex]
Horizontal component of force=[tex]16\times 0.819=13.1lb[/tex]
Hence, horizontal component of force=13 lb
Answer:b.13 lb