Answer:
2.87 V₀
Explanation:
d₀ = diameter of vessel before blood enters blocked portion
d = diameter of vessel in the blocked portion = 0.59 d₀
V₀ = speed of blood before blocked portion
V = speed of blood in blocked portion
Using equation of continuity
(0.25) π d₀² V₀ = (0.25) π d² V
d₀² V₀ = (0.59 d₀)² V
d₀² V₀ = (0.59)² d₀² V
V = 2.87 V₀
Answer:
The blood enters the blocked portion of the vessel at [tex]0.1681V[/tex].
Explanation:
The blood is flowing through the vessel.
Let the radius of the vessel is [tex]r[/tex].
At some point, the radius of the vessel is decreased by 59.0%. So, the radius at the point will be,
[tex]r'=r-.59r\\r'=.41r[/tex]
The velocity of the blood initially is [tex]V_0[/tex].
Now, apply the continuity equation to get the velocity of blood at the contracted point. Let [tex]a[/tex] and [tex]a'[/tex] are the area of the vessel at initial point and contracted point, respectively.
[tex]aV_0=a'V\\\pi r^2V_0=\pi r'^2V\\r^2V_0= (0.41r)^2V\\V_0=0.1681V[/tex]
Thus, the blood enters the blocked portion of the vessel at [tex]0.1681V[/tex].
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https://brainly.com/question/24905814?referrer=searchResults
