contestada

If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
A. -6
B. Square root of -5
C. 6 - Square root of 5
D. 6 + Square root of 5

Respuesta :

SaniShahbaz

Answer:

-[tex]\sqrt{5}[/tex]

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

  • One answer with positive square root
  • One answer with negative square root

For example, for the equation:

[tex]x^{2}=3[/tex]

If we take the square root of both sides, the answers will be:

[tex]x=\sqrt{3} \text{ or } x= -\sqrt{3}[/tex]

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and [tex]\sqrt{5}[/tex]. Therefore, the 3rd root of the polynomial function f(x) had to be -[tex]\sqrt{5}[/tex]

It seems you made error while writing option B, it should be - square root of 5.

Answer:

B

Step-by-step explanation:

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