Answer:
a) Tmax=827.12N
b) Tmin = 626.22N
c) 776.895 N
Explanation:
Given:
Mass of wrecking ball M1=63.9 Kg
Mass of the chain M2=20.5 Kg
acceleration due to gravity, g=9.8m/s²
Now,
(a)The Maximum Tension generated in the chain,
Tmax=(M1+M2)×g)
Tmax=(M1+M2)×(9.8 m/s²)
Tmax=(63.9+ 20.5)×(9.8 m/s²)
Tmax=827.12N
(b) The Minimum Tension Tmin will be due to the weight of the wrecking ball only
Mathematically,
Tmin=weight of the wrecking ball
Tmin = 63.9kg×9.8m/s²
Tmin = 626.22N
(c)Now. the tension at 3/4 from the bottom of the chain
In this part we have to use only 75% of the chain i.e the weight acting below the point of consideration
thus, the tension will be produced by the weight of the 3/4 part of the chain and the wrecking ball
Therefore, the weight of the 3/4 part of the chain = [tex]\frac{3}{4}\times 20.5\times 9.8 N[/tex]
= 150.675 N
Hence, the tension at a point 3/4 of the way up from the bottom of the chain will be = 150.675 N + (63.9×9.8) N = 776.895 N
