Respuesta :
Answer : The vapor pressure of solution is 23.67 mmHg.
Solution:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
[tex]\frac{p^o-p_s}{p^o}=\frac{w_2M_1}{w_1M_2}[/tex]
where,
[tex]p^o[/tex] = vapor pressure of pure solvent (water) = 23.76 mmHg
[tex]p_s[/tex] = vapor pressure of solution= ?
[tex]w_2[/tex] = mass of solute (sucrose) = 12.25 g
[tex]w_1[/tex] = mass of solvent (water) = 176.3 g
[tex]M_1[/tex] = molar mass of solvent (water) = 18.02 g/mole
[tex]M_2[/tex] = molar mass of solute (sucrose) = 342.3 g/mole
Now put all the given values in this formula ,we get the vapor pressure of the solution.
[tex]\frac{23.76-p_s}{23.76}=\frac{12.25\times 18.02}{176.3\times 342.3}[/tex]
[tex]p_s=23.67mmHg[/tex]
Therefore, the vapor pressure of solution is 23.67 mmHg.
