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In the pendulum formula, we use g=9.8 m/s^2 for the acceleration due to gravity on Earth. But what about on Venus? If an astronaut on the surface of Venus swings a 1-meter long pendulum, and it has a period of 2.11 seconds, what is the acceleration due to gravity, g, on Venus?

In the pendulum formula we use g98 ms2 for the acceleration due to gravity on Earth But what about on Venus If an astronaut on the surface of Venus swings a 1me class=

Respuesta :

mckee107

Answer:

8.9 (just got it on Apex)

Step-by-step explanation:

(guessed correct on Apex due to other questions on Brainly that were relative to this one)

Answer:

Option A is the correct answer.

Step-by-step explanation:

Period of simple pendulum is given by the expression,

            [tex]T=2\pi \sqrt{\frac{l}{g}}[/tex]

Where l is the length of pendulum, g is acceleration due to gravity.

Here given for Venus

         Period, T = 2.11 s

        Length of pendulum, l = 1 m

     We need to find acceleration due to gravity, g

Substituting

            [tex]2.11=2\pi \sqrt{\frac{1}{g}}\\\\\sqrt{g}=\frac{2\pi}{2.11}\\\\g=8.87m/s^2[/tex]

Acceleration due to gravity of Venus = 8.9 m/s²

Option A is the correct answer.

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