Respuesta :
Answer : The heat of this reaction of AgCI formed will be, 66.88 KJ
Explanation :
First we have to calculate the heat of the reaction.
[tex]q=m\times c\times (T_{final}-T_{initial})[/tex]
where,
q = amount of heat = ?
[tex]c[/tex] = specific heat capacity = [tex]4.18J/g.K[/tex]
m = mass of substance = 120 g
[tex]T_{final}[/tex] = final temperature = [tex]22^oC=273+22=295K[/tex]
[tex]T_{initial}[/tex] = initial temperature = [tex]22.8^oC=273+22.8=295.8K[/tex]
Now put all the given values in the above formula, we get:
[tex]q=120g\times 4.18J/g.K\times (295.8-295)K[/tex]
[tex]q=401.28J[/tex]
Now we have to calculate the number of moles of [tex]AgNO_3[/tex] and [tex]HCl[/tex].
[tex]\text{Moles of }AgNO_3=\text{Molarity of }AgNO_3\times \text{Volume of solution}[/tex]
[tex]\text{Moles of }AgNO_3=0.20mole/L\times 0.03L=0.006mole[/tex]
[tex]\text{Moles of }HCl=\text{Molarity of }HCl\times \text{Volume of solution}[/tex]
[tex]\text{Moles of }HCl=0.10mole/L\times 0.1L=0.01mole[/tex]
Now we have to calculate the limiting reactant.
The balanced chemical reaction will be,
[tex]AgNO_3+HCl\rightarrow AgCl+HNO_3[/tex]
As, 1 mole of [tex]AgNO_3[/tex] react with 1 mole of HCl
So, 0.006 mole of [tex]AgNO_3[/tex] react with 0.006 mole of HCl
From this we conclude that, [tex]HCl[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]AgNO_3[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of AgCl.
The given balanced reaction is,
[tex]Ag^++Cl^-\rightarrow AgCl[/tex]
From this we conclude that,
1 mole of [tex]Ag^+[/tex] react with 1 mole [tex]Cl^-[/tex] to produce 1 mole of [tex]AgCl[/tex]
0.006 mole of [tex]Ag^+[/tex] react with 0.006 mole [tex]Cl^-[/tex] to produce 0.006 mole of [tex]AgCl[/tex]
Now we have to calculate the heat of this reaction of AgCI formed.
As, 0.006 mole of AgCl produced the heat = 401.28 J
So, 1 mole of AgCl produced the heat = [tex]\frac{401.28}{0.006}=66880J=66.88KJ[/tex]
Therefore, the heat of this reaction of AgCI formed will be, 66.88 KJ
