Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
[tex]m_1v_1+m_2v_2=(m_1+m_2)V[/tex]
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
[tex]v_2=-\dfrac{m_1v_1}{m_2}[/tex]
[tex]v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}[/tex]
[tex]v_2=-1.47\ m/s[/tex]
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
