A 3.0 kg ball tied to the end of a 50 cm long string being swung in a circle in a horizontal plane at constant speed. If the tension of the string is 3.8 N, what is the speed of the ball?

Question 31 options:

A)

1.2 m/s
B)

1.0 m/s
C)

1.4 m/s
D)

0.8 m/s

Respuesta :

Answer:

The speed of the ball is 0.8 m/s.

(D) is correct option.

Explanation:

Given that,

mass of ball = 3.0 kg

length = 50 cm

We need to calculate the speed of the ball

Using relation between the centripetal force and tension

[tex]\dfrac{mv^2}{r}=T[/tex]

[tex]v^2=\dfrac{T\times r}{m}[/tex]

Where, m = mass

T = tension

r = radius

Put the value into the formula

[tex]v=\sqrt{\dfrac{3.8\times50\times10^{-2}}{3.0}}[/tex]

[tex]v=0.8\ m/s[/tex]

Hence, The speed of the ball is 0.8 m/s.