Answer:
The horizontal distance traveled by the ball before it hits the ground is 48.85 meters.
Explanation:
It is given that,
Speed of golf ball, v = 25 m/s
Angle above horizontal or angle of projection, θ = 65°
We need to find the distance travelled by the ball before it hots the ground or in other words we need to find the range. It is given by R.
[tex]R=\dfrac{v^2\ sin2\theta}{g}[/tex]
[tex]R=\dfrac{(25\ m/s)^2\ sin2(65)}{9.8\ m/s^2}[/tex]
R = 48.85 m
So, the distance travelled by the ball before it hots the ground is 48.85 meters. Hence, this is the required solution.
