Answer: 0.0136
Step-by-step explanation:
Given : Mean : [tex]\mu=\ 25[/tex]
Standard deviation : [tex]\sigma= 3.2[/tex]
Sample size : [tex]n=50[/tex]
The formula to calculate the z-score :-
[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
For x = 24
[tex]z=\dfrac{24-25}{\dfrac{3.2}{\sqrt{50}}}=-2.20970869121\aprox-2.21[/tex]
The P-value =[tex]P(z\leq24)=0.0135526\approx0.0136[/tex]
Hence, the probability that the sample mean age for 50 randomly selected women to marry is at most 24 years = 0.0136