Answer:
Heat generated in the rod is 8.33 watts.
Explanation:
It is given that,
Length of rod, l = 2 m
Area of cross section, [tex]A=2\ mm\times 2\ mm=4\ mm^2=4\times 10^{-6}\ m^2[/tex]
Resistivity of rod, [tex]\rho=6\times 10^{-8}\ \Omega-m[/tex]
Potential difference, V = 0.5 V
The value of resistance is given by :
[tex]R=\rho\dfrac{l}{A}[/tex]
[tex]R=6\times 10^{-8}\ \Omega-m\times \dfrac{2\ m}{4\times 10^{-6}\ m^2}[/tex]
R = 0.03 ohms
Let H is the rate at which heat is generated in the rod . It is given by :
[tex]\dfrac{H}{t}=I^2R[/tex]
Since, [tex]I=\dfrac{V}{R}[/tex]
[tex]\dfrac{H}{t}=\dfrac{V^2}{R}[/tex]
[tex]\dfrac{H}{t}=\dfrac{(0.5)^2}{0.03}[/tex]
[tex]\dfrac{H}{t}=8.33\ watts[/tex]
So, the at which heat is generated in the rod is 8.33 watts. Hence, this is the required solution.
