contestada

A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53 riders at one time, with an average mass per rider of 69.0 kg .

Estimate the power required to operate the tow

Respuesta :

Answer:

P = 34034.2 Watt

Explanation:

As we know that the slope angle is given as

[tex]\theta = 15.6^0[/tex]

now the weight of the rider along the slope is given as

[tex]W = mgsin\theta[/tex]

[tex]W = 69(9.81)sin15.6[/tex]

[tex]W = 182 N[/tex]

now total weight of all 53 riders along the slope is given as

[tex]F = 53 W[/tex]

[tex]F = 9647.5 N[/tex]

now the speed of the rope is given as

[tex]v = 12.7 km/h = 3.53 m/s[/tex]

now the power required is given as

[tex]P = F.v[/tex]

[tex]P = 9647.5(3.53) [/tex]

[tex]P = 34034.2 Watt[/tex]

onyebuchinnaji

The power required to operate the tow is 34020.45 W.

Weight of a single rider

The weight of a single rider is calculated as follows;

[tex]W = mgsin(\theta)\\\\W = (69 \times 9.8) sin(15.6)\\\\W = 181.84 \ N[/tex]

Weight of the 53 riders

W = 53 x 181.84

W = 9637.52 N

Power required to operate the tow

The power required to operate the tow is calculated as follows;

P = Fv

where;

  • F is the upward force due to weight of the riders = 9637.52 N
  • v is speed of the rope = 12.7 km/h = 3.53 m/s

P = 9637.52 x 3.53 = 34020.45 W

Learn more about power here: https://brainly.com/question/25263760

Otras preguntas