Explanation:
It is given that,
Object distance, u = -3.75 cm (negative always)
Focal length, f = +4 cm
We need to find the angular magnification of the lens. Firstly, we will find the image distance using lens formula as :
[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{4}+\dfrac{1}{(-3.75)}[/tex]
v = -60 cm
Angular magnification is as the ratio of image distance to the object distance i.e.
[tex]m=\dfrac{v}{u}[/tex]
[tex]m=\dfrac{-60\ cm}{-3.75\ cm}[/tex]
m = +16
So, the angular magnification of the insect is 16. Hence, this is the required solution.
The angular magnification is mathematically given as
m = +16
Question Parameter(s):
A small insect is placed 3.75 cm from a +4.00 −cm -focal-length lens
Generally, the equation for the is mathematically given as
[tex]\frac{1}{f}=\frac{1}{v}-\frac{1}{u}[/tex]
Therefore
[tex]\frac{1}{v}=\frac{1}{f}+\frac{1}{u}[/tex]
[tex]\frac{1}{v}=\frac{1}{4}+\frac{1}{(-3.75)}[/tex]
v = -60 cm
In conclusion, Angular magnification is
m=v/u
m=-60 cm-3.75cm
m = +16
Read more about Wave
https://brainly.com/question/3004869
