Answer:
0.8
Explanation:
Given:
[tex]h_{oil}[/tex] = 0.35m
[tex]h_{water}[/tex] = 0.28m
Equating the pressure in the manometer at both ends
we have
Pressure at the left limb = Pressure at right limb
[tex]\rho_{oil} gh_{oil}=\rho_{water} gh_{water}[/tex]
substituting the values in the above equation, we get
[tex]\rho_{oil}\times g\times 0.35=\rho_{water}\times g\times 0.28[/tex]
[tex]\frac{\rho_{oil}}{\rho_{water}} =\frac{ 0.28}{0.35}[/tex]
[tex]\frac{\rho_{oil}}{\rho_{water}} =0.8[/tex]
we know that specific gravity is defined as the ratio of the density of the fluid with respect to the density of water
thus, SG of oil = 0.8
