Answer:
The combined speed of the woman and the skateboard is 6.67 m/s.
Explanation:
It is given that,
Mass of woman, m₁ = 60 kg
Speed of woman, v = 10 m/s
The woman jumps onto a giant skateboard of mass, m₂ = 30 kg
Let V is the combined speed of the woman and the skateboard. It can be calculated using the conservation of momentum as :
[tex]60\ kg\times 10\ m/s+30(0)=(60\ kg+30\ kg)V[/tex]
On solving the above equation we get V = 6.67 m/s
So, the combined speed of the woman and the skateboard is 6.67 m/s. Hence, this is the required solution.
