What must be a factor of the polynomial function f(x) graft on the coordinate plane below

We know that if the zeros (or intercepts) of an equation are [tex] r _ 1 [/tex] and [tex] r _ 2 [/tex] then the factors for this equation will be [tex] ( x - r _ 1 ) [/tex] and [tex]( x - r _ 2 ) [/tex].

From the graph, we can see that it intercepts the x axis at [tex]1[/tex] and [tex]6[/tex]. So the roots will be [tex](x-1)[/tex] and [tex](x-6)[/tex].

Therefore, the correct answer option is B. (x - 1).

luisejr77 luisejr77 · Answer 2 · 2019-07-12T21:12:59+02:00

Answer: SECOND OPTION.

Step-by-step explanation:

We can verify each option by making eac equal to zero and solving for "x":

First option

[tex]x-3=0\\x=0+3\\x=3[/tex]

The first option is not a factor of the polynomial function, because the parabola does not intersect the x-axis at [tex]x=3[/tex].

Second option

[tex]x-1=0\\x=0+1\\x=1[/tex]

The second option is a factor of the polynomial function, because the parabola intersects the x-axis at [tex]x=1[/tex].

Third option

[tex]x+1=0\\x=0-1\\x=-1[/tex]

The third option is not a factor of the polynomial function, because the parabola does not intersect the x-axis at [tex]x=-1[/tex].

Fourth option

[tex]x+3=0\\x=0-3\\x=-3[/tex]

The fourth option is not a factor of the polynomial function, because the parabola does not intersect the x-axis at [tex]x=-3[/tex].