Answer:
The distance between adjacent antinodes of the standing wave is 1.25 m.
Explanation:
Given that,
Frequency f= 120 MHz
We need to calculate the distance between adjacent antinodes of the standing wave
Using formula of distance
[tex]\Delta x=\dfrac{\lambda}{2}[/tex].....(I)
We know that,
[tex]\lambda=\dfrac{c}{f}[/tex]
Put the value of [tex]\lambda[/tex] in to the equation (I)
[tex]\Delta x=\dfrac{c}{2f}[/tex]
Where, c = speed of light
f = frequency
Put the all value into the formula
[tex]\Delta x=\dfrac{3\times10^{8}}{2\times120\times10^{6}}[/tex]
[tex]\Delta x=1.25\ m[/tex]
Hence, The distance between adjacent antinodes of the standing wave is 1.25 m.