Answer:
The work done on the test charge is 4.5 joules
Explanation:
It is given that,
Electric potential difference, [tex]V=1000\ V[/tex]
Charged particle, [tex]q=4.5\times 10^{-3}\ C[/tex]
Work done on the test charge is given by the product of test charge and potential difference i.e.
W = q × V
[tex]W=4.5\times 10^{-3}\ C\times 1000\ V[/tex]
W = 4.5 Joules
So, the work done on the test charge is 4.5 joules. Hence, this is the required solution.
