Answer:
The output power is 2 kW
Explanation:
It is given that,
Number of turns in primary coil, [tex]N_p=250[/tex]
Number of turns in secondary coil, [tex]N_s=500[/tex]
Voltage of primary coil, [tex]V_p=200\ V[/tex]
Current drawn from secondary coil, [tex]I_s=5\ A[/tex]
We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :
[tex]\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}[/tex]
[tex]\dfrac{250}{500}=\dfrac{200}{V_s}[/tex]
[tex]V_s=400\ V[/tex]
So, the power output is :
[tex]P_s=V_s\times I_s[/tex]
[tex]P_s=400\ V\times 5\ A[/tex]
[tex]P_s=2000\ watts[/tex]
or
[tex]P_s=2\ kW[/tex]
So, the output power is 2 kW. Hence, this is the required solution.
