Answer:
[tex]43.28\frac{lbf}{in^3}=43.28\times 27460.68\frac{kg}{m^3}=1188498.44\frac{kg}{m^3}[/tex]
Explanation:
Here the given values corresponds to the density of a substance
The density of a substance in standard SI unit is given as Kg/m³.
Given value = 43.28lbf/in³
also
we know,
1 lbf = 0.45kg
1in = 0.0254 m
thus,
[tex]\frac{1lbf}{1in^3}=\frac{0.45kg}{0.0254^3m^3}=27460.68\frac{kg}{m^3}[/tex]
therefore,
[tex]43.28\frac{lbf}{in^3}=43.28\times 27460.68\frac{kg}{m^3}=1188498.44\frac{kg}{m^3}[/tex]
