Respuesta :
Answer:
One other zero is 2+3i
Step-by-step explanation:
If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.
The conjugate of (a+b) is (a-b).
The conjugate of (a-b) is (a+b).
The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.
Ok so we have two zeros 2-3i and 2+3i.
This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.
I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).
(x-(2-3i))(x-(2+3i))
Foil!
First: x(x)=x^2
Outer: x*-(2+3i)=-x(2+3i)
Inner: -(2-3i)(x)=-x(2-3i)
Last: (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)
---------------------------------Add together:
x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)
Simplifying:
x^2-2x-3ix-2x+3ix+4+9 (since i^2=-1)
x^2-4x+13 (since -3ix+3ix=0)
So x^2-4x+13 is a factor of the given polynomial.
I'm going to do long division to find another factor.
Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.
x^2+1
---------------------------------------
x^2-4x+13| x^4-4x^3+14x^2-4x+13
-( x^4-4x^3+ 13x^2)
------------------------------------------
x^2-4x+13
-(x^2-4x+13)
-----------------
0
So the other factor is x^2+1.
To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.
[tex]x^2+1=0[/tex]
[tex]x^2=-1[/tex]
[tex]x=\pm \sqrt{-1}[/tex]
[tex]x=\pm i[/tex]
So the zeros are i, -i , 2-3i , 2+3i
The zeros of a function are the points where the function cross the x-axis.
One other zero of [tex]\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}[/tex] is 2 + 3i.
The zero of [tex]\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}[/tex] is given as:
[tex]\mathbf{Zero = 2 - 3i}[/tex]
The above number is a complex number.
If a complex number a + bi is the zero of a function f(x), then the conjugate a - bi is also the zero of f(x).
This means that, one other zero of [tex]\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}[/tex] is 2 + 3i.
Read more about zeros of functions at:
https://brainly.com/question/22101211
