Answer:
The magnetic force on the section of wire is [tex]-2.925\hat{j}\ N[/tex].
Explanation:
Given that,
Current [tex]I = 2.60\hat{i}\ A[/tex]
Length = 0.750 m
Magnetic field [tex]B = 1.50\hat{k}\ T[/tex]
We need to calculate the magnetic force on the section of wire
Using formula of magnetic force
[tex]\vec{F}=l\vec{I}\times\vec{B}[/tex]
[tex]\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}[/tex]
Since, [tex]\hat{i}\times\hat{k}=-\hat{j}[/tex]
[tex]\vec{F}=-2.925\hat{j}\ N[/tex]
Hence, The magnetic force on the section of wire is [tex]-2.925\hat{j}\ N[/tex].
