Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a photon of this radiation

Respuesta :

Answer : The frequency of a photon of radiation is, [tex]4.47\times 10^9s^{-1}[/tex]

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : [tex](1nm=10^{-9}m)[/tex]

So, the wavelength of the radiation = 670.8 nm = [tex]670.8\times 10^{-9}m[/tex]

Now we have to calculate the frequency of a photon of radiation.

Formula used : [tex]\nu =\frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency of a photon of radiation

[tex]\lambda[/tex] = wavelength of the radiation

c = speed of light = [tex]3\times 10^8m/s[/tex]

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

[tex]\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}[/tex]

[tex]\nu =4.47\times 10^9s^{-1}[/tex]

Therefore, the frequency of a photon of radiation is, [tex]4.47\times 10^9s^{-1}[/tex]

Answer:

[tex]f=4.47x10^5GHz[/tex]

Explanation:

Hello,

In this case, we relate the speed of light, wavelength and frequency via the shown below equation expressed in the proper SI system of units:

[tex]f=\frac{c}{\lambda } =\frac{3x10^8m/s}{670.8nm*\frac{1x10^{-9}m}{1nm} } =4.47x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ f=4.47x10^5GHz[/tex]

Best regards.