The magnetic field in the middle of the capacitor plates at a distance d from the center, as a function of time t is
Explanation:
A parallel-plate capacitor has circular plates of area A separated by a distance d. A thin straight wire of length d lies along the axis of the capacitor and connects the two plates. This wire has a resistance R. The exterior terminals of the plates are connected to a source of alternating emf with a voltage [tex]V = V_0 sin(\omega t)[/tex]
What is the magnetic field between the capacitor plates at a distance r from the axis ? Assume that r is less than the radius of the plates.
The magnetic field is area around the magnet which there is magnetic force. The calculation of the magnetic field of a current distribution can be carried out using Ampere's law. It is stated that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop
The magnetic field lines inside the capacitor will formed concentric circles, and it is centered around the resistor. Therefore the path integral of the magnetic field around a circle of radius r is equal to
[tex]\int\limits {path} B.dl = 2 \pi r B(r)[/tex]
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