Answer:
The coefficient of friction of the sled is 0.115
Explanation:
It is given that,
Mass of the sled, m = 46.6 kg
Frictional force acting on it, F = 52.9 N
We need to find the coefficient of friction. Frictional force is given by :
[tex]F=\mu mg[/tex]
[tex]\mu=\dfrac{F}{mg}[/tex]
[tex]\mu=\dfrac{52.9\ N}{46.6\ kg\times 9.8\ m/s^2}[/tex]
[tex]\mu = 0.115[/tex]
So, the coefficient of friction of the sled is 0.115. Hence, this is the required solution.