Answer:
57N
Explanation:
[tex]F_F = \mu F_N = \mu mg = 0.11 \times 53 kg \times 9,8 \frac{m}{s^{2} }[/tex]
Answer:
Force, F = 57.134 N
Explanation:
It is given that,
Mass of the sled, m = 53 kg
Coefficient of kinetic friction, [tex]\mu_k=0.11[/tex]
We need to find the force of friction felt by sled. The force of friction is given by :
[tex]F=\mu mg[/tex]
[tex]F=0.11\times 53\ kg\times 9.8\ m/s^2[/tex]
F = 57.134 N
So, the force of friction felt by the sled is 57.134 N. Hence, this is the required solution.
