Respuesta :

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Answer:

[tex]\boxed{2.5\times 10^{-3}\text{ mol/L}}[/tex]

Explanation:

pH = -log[H₃O⁺]

H₃O⁺ = 10^(-pH)  = 10^(-2.60) mol/L = 2.5× 10⁻³ mol/L