a place from this table is chosen at random. let event A= the place is a city

Answer:
5/7 is the correct answer
Step-by-step explanation:
The probability of the place is at city are:
The total probability of the place is at city / The total possible outcomes
= 5 / 7
Hope this help you :3
Answer:
There are 7 places shown in the table which are , →{Rome, Tokyo, Houston, Peru, Miami, Toronto, Canada}
Out of which 5 are cities.
City={Rome, Tokyo, Houston,Miami, Toronto,}=5
It is given that a,place from the city is chosen.
Probability of an Event
[tex]=\frac{\text{Total Favorable event}}{\text{Total possible outcome}}[/tex]
Probability of selecting a city from 7 places in which 5 are cities
[tex]P(A)=\frac{_{1}^{5}\textrm{C}}{_{1}^{7}\textrm{C}}\\\\P(A)=\frac{5}{7}\\\\P(A^c)=1-P(A)\\\\=1-\frac{5}{7}\\\\=\frac{2}{7}[/tex]
Option B